Trigonometry, find the minimum of tan(a).tan(b).tan(c)

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Michael_Light
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Homework Statement



1. Given a,b,c are acute angles and a + b + c =180. find the minimum of tan(a).tan(b).tan(c)

2. Prove that if a+b+c=90, then tan(a)+tan(b)+tan(c) >= 31/2

Homework Equations


The Attempt at a Solution



I don't even have any ideas how should i start to find/prove them... any hints?
 
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For the first one I'd try to expand the left side after taking the tangent of both sides.

tan(a+b+c) = tan(180°)
 
Following rock.freak's suggestion, I would write the tangent of the third angle in terms of the tangents of the other two angles, and would use the relation between geometric and arithmetic means.

ehild
 
tan(a)*tan(b)*tan(c) = -tan(b+c) *tan(b)*tan(c) = (tanb+tanc)/(1-tanb*tanc) *tanb*tanc
call S = tanb + tanc and P = tanb * tanc S^2>= 4P this should be easy from here on
 
Still cannot do... how bout question (2)? Any hints?
 
you can use the langrange function to do it, it is quite easy if u use it
 
We can not help if you do not show any attempt.

ehild
 
NeroKid said:
you can use the langrange function to do it, it is quite easy if u use it

Note that it is Precalculus Math.

ehild
 
then just have to expand them to the sum and the product which is pretty much easier to solve
 
Michael_Light said:
1. Given a,b,c are acute angles and a + b + c =180. find the minimum of tan(a).tan(b).tan(c)
ehild said:
Following rock.freak's suggestion, I would write the tangent of the third angle in terms of the tangents of the other two angles, and would use the relation between geometric and arithmetic means.

ehild
NeroKid said:
tan(a)*tan(b)*tan(c) = -tan(b+c) *tan(b)*tan(c) = (tanb+tanc)/(1-tanb*tanc) *tanb*tanc
call S = tanb + tanc and P = tanb * tanc S^2>= 4P this should be easy from here on
Michael_Light said:
Still cannot do...

Michael, are you trying?

You need to minimise (tanb+tanc)/(1-tanb*tanc) *tanb*tanc …

surely you have some idea how to do that?​