1. Oct 27, 2011 #1

   highc1157

   

   Hi,
   
   I am having trouble creating a differential equation from my flow line that models population of deer. The flow line has two nodes, a sink (attractor), and a source (repeller). I need to come up with a D.E from the flow line.
   
   my "skeleton equation looks like this"
   
   dp/dt = p(1-(p/4))((p/6)-1)(1-(y/8))
   
   but this doesnt work, i've rearranged so many ways and doesnt match the flow line

    

   highc1157, Oct 27, 2011
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3. Oct 28, 2011 #2

   jackmell

   

   How about:
   
   [tex]\frac{dy}{dt}=y(1-y)(2-y)[/tex]
   
   y=2 is a source and y=1 is a sink. May not match exactly what you want but it does include the type of equilibrium points you want.

    

   jackmell, Oct 28, 2011

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