Trouble creating differential equation from a flow line

[highc1157]

Hi,

I am having trouble creating a differential equation from my flow line that models population of deer. The flow line has two nodes, a sink (attractor), and a source (repeller). I need to come up with a D.E from the flow line.

my "skeleton equation looks like this"

dp/dt = p(1-(p/4))((p/6)-1)(1-(y/8))

but this doesn't work, I've rearranged so many ways and doesn't match the flow line

 

[jackmell]

How about:

$$\frac{dy}{dt}=y(1-y)(2-y)$$

y=2 is a source and y=1 is a sink. May not match exactly what you want but it does include the type of equilibrium points you want.