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Trouble creating differential equation from a flow line

  1. Oct 27, 2011 #1
    Hi,

    I am having trouble creating a differential equation from my flow line that models population of deer. The flow line has two nodes, a sink (attractor), and a source (repeller). I need to come up with a D.E from the flow line.

    my "skeleton equation looks like this"

    dp/dt = p(1-(p/4))((p/6)-1)(1-(y/8))

    but this doesnt work, i've rearranged so many ways and doesnt match the flow line
     
  2. jcsd
  3. Oct 28, 2011 #2
    How about:

    [tex]\frac{dy}{dt}=y(1-y)(2-y)[/tex]

    y=2 is a source and y=1 is a sink. May not match exactly what you want but it does include the type of equilibrium points you want.
     
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