Trouble understanding collisions

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    Collisions
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SUMMARY

This discussion centers on the concept of momentum and kinetic energy conservation during collisions, specifically involving a light mass colliding with a heavy mass. The initial conditions include a light mass moving at velocity v and a heavy mass at rest, leading to a total momentum of mv and total kinetic energy of (mv^2)/2. The participant explores the implications of the light mass reversing direction post-collision, concluding that for energy conservation, the rebound velocity must be adjusted based on mass ratios, specifically k = (M-m)/(M+m). This analysis clarifies that equal speed rebound is unphysical and reinforces the principles of momentum and energy conservation.

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Opus_723
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So we had some questions in lab today that left me confused. Someone please tell me what I'm not understanding here?

We start with a light mass moving at velocity v, having linear momentum p=mv and kinetic energy (mv^2)/2, and a heavy mass at rest, with linear momentum p=M(0)= 0 and kinetic energy (m(0^2))/2= 0. The total momentum of the system is 0 + mv = mv, and the total kinetic energy is 0 + (mv^2)/2 = (mv^2)/2.

Suppose the light mass collides with the heavy mass in such a way that it has a new velocity nearly equal to its original velocity but opposite in direction. It's new momentum is m(-v)= -mv, and its new kinetic energy is (m(-v)^2)/2= (mv^2), which is the same kinetic energy it began with. Since the initial momentum of the system was p = mv, we have
mv = x -mv, where x is the final momentum of the heavy mass. So x = 2mv. Since the heavy mass has a momentum, it must have kinetic energy. But the light mass has the same kinetic energy that it had at the start, so adding any energy to that would give us more kinetic energy than we started with.

What did I miss?
 
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Maybe I spoke too soon. I think I figured it out myself.

My first suspicion was that the situation the lab gave me was unphysical. That an object could never bounce back with the same speed it started with.

So I decided to work out the problem in more general terms so that if you start with the situation above, the light mass has a velocity -kv after the collision for some value of k. Then I applied conservation of kinetic energy and found that in order for energy to be conserved, k must be equal to (M-m)/(M+m). This is zero for equal masses and approaches one as the difference between the masses increases, but can never equal one.

So yay!

EDIT: For anyone wondering why I posted for help when I had an idea of where to go next, it's because the first time I tried the above, I lost a negative somewhere and got a silly result that suggested that objects ALWAYS bounce back with equal speed. After posting, I decided to double check my work. I'll just let that be a lesson to myself.
 
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