Trouble with Integrating (1/x^2)*sec(1/x)*tan(1/x)dx Using u-Substitution

[fiziksfun]

So this is my first year of calculus and we're doing integrals using u-substitution

I'm having trouble with this integral:

integral of (1/x^2)*sec(1/x)*tan(1/x)dx

i let u=(1/x)
so du=(1/x^2)dx
so du(x^2)=dx

If I do this, the integral works out perfectly since the x^2 cancel out

so it equals sec(u) + C

HOWEVER, my question is
if i let u = (1/x)

why don't i replace the (1/x^2) (in the beginning of the integral) with u^2

CAN SOMEONE HELP ME??

 

[Snazzy]

First of all, the derivative of \frac{1}{x} is not \frac{1}{x^2}


Second of all, if u^2 = \frac{1}{x^2}


then 2udu = \frac{-2}{x^3}dx


And you haven't made anything simpler for yourself.

 

[fiziksfun]

the derivative of 1/x is -1/x^2 correct? sorrrybut if i were to do a u substitution like

integral of tan^4(x)*sec^2(x)

and i let u=tan x
then du*sec^2x=dxand that leads to the integral of u^4, correct? I'm confused

 

[Snazzy]

I don't follow. The derivative of u with respect to x is du / dx and the derivative of tan x is (secx)^2. so du / dx = (secx)^2.

 

[fiziksfun]

right. so dx = du / (secx)^2 so
if i substitute that back into the original integral the (secx)^2 cancel out.
is the clearer?

 

[Snazzy]

But you can't let u = tan(x) because there is no tan(x) in the integral. There's a tan(1/x).

 

[fiziksfun]

okk new problem, just to show what I am trying to say
lets take this integral
http://archives.math.utk.edu/visual.calculus/4/substitutions.1/int1-2.gif

the solution is
http://archives.math.utk.edu/visual.calculus/4/substitutions.1/sint1-2.gif

we let u=cosx

when we substitute it back into the original integral we have u^3

that's what confuses me. why can i do u^3 there and not
u^2 in the my original integral

does that make sense??

 

[Snazzy]

The difference is that you are saying "let u^2 = some function, whereas in this question, we let u = some function, and when you substitute u back into the integral, it just happens to become u^3.

What you want to do is let u = some function so that du = (some function that's already inside the integral)dx. This simplifies things in terms of u and du with no X's.