Trouble with Limit of cot^2(x)/(1-csc(x))

  • Thread starter Thread starter BrownianMan
  • Start date Start date
  • Tags Tags
    Limit
Click For Summary
SUMMARY

The limit as x approaches π/2 of the expression (cot²(x))/(1-csc(x)) can be resolved by multiplying the numerator and denominator by (1 + csc(x)). This technique utilizes the identity cot²(x) = csc²(x) - 1, which simplifies the limit evaluation. The final result confirms that applying trigonometric identities is essential for solving limits involving cotangent and cosecant functions.

PREREQUISITES
  • Understanding of trigonometric identities, specifically cotangent and cosecant functions.
  • Familiarity with limit evaluation techniques in calculus.
  • Knowledge of algebraic manipulation of fractions.
  • Experience with approaching limits involving indeterminate forms.
NEXT STEPS
  • Study the application of trigonometric identities in limit problems.
  • Learn about L'Hôpital's Rule for resolving indeterminate forms.
  • Explore advanced limit techniques, including epsilon-delta definitions.
  • Investigate the behavior of trigonometric functions near their asymptotes.
USEFUL FOR

Students of calculus, mathematics educators, and anyone seeking to deepen their understanding of limits involving trigonometric functions.

BrownianMan
Messages
133
Reaction score
0
For some reason, I'm having trouble with the following:

limit as x-->pi/2 (cot^2(x))/(1-csc(x))

Any help would be appreciated!
 
Physics news on Phys.org
BrownianMan said:
For some reason, I'm having trouble with the following:

limit as x-->pi/2 (cot^2(x))/(1-csc(x))

Any help would be appreciated!

I would multiply by 1 + csc(x) over itself. Keep in mind the identity that involved cot^2(x) and csc^2(x).
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 27 ·
Replies
27
Views
4K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
4K