Troubleshooting a Weather Balloon Expansion Problem

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A weather balloon is designed to expand to a maximum radius of 30 m at an altitude with specific pressure and temperature conditions. The initial calculations using the ideal gas law led to an incorrect radius at lift-off. The correct approach involves using the relationship of volume and temperature, showing that the ground volume is 16% of the final volume. Consequently, the initial radius is determined by taking the cube root of the volume ratio. The discussion highlights the importance of understanding gas laws and volume relationships in solving the problem accurately.
PrideofPhilly
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Homework Statement



A weather balloon is designed to expand to
a maximum radius of 30 m when in flight at
its working altitude where the air pressure is
0.033 atm and the temperature is 95 K.
If the balloon is filled at atmospheric pres-
sure and 462 K, what is its radius at lift-off?

Homework Equations



PV = nRT
Volume = 4/3πr^3

The Attempt at a Solution



First, I used the ideal gas law to find n:

(0.033)(4/3π(30)^3) = n(8.31)(95)
n = 4.727610453 mol

Then, I solved for r:

V = nRT/P
4/3πr^3 = (4.727610453)(8.31)(462)/1 atm
r = 11.30381236 m (WRONG ANSWER)

What am I doing wrong?
 
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So PV/T is constant, you don't actually need the number of moles.
V1 = (T1/P1) * (P2V2/T2)
= (462/1) * (0.033*V2/95)
V1 = 0.16 V2

So the ground volume is 16% off the final volume, an the radius goes as the cube root of volume, so the initial radius is 0.16^0.33 of 30m
 
where did you get the 0.33 from?
 
PrideofPhilly said:
where did you get the 0.33 from?

He means to the power of one third (the cube root, as he said).
 
nevermind, i got it! thank you!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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