MHB Troubleshooting Inequality: Can't Seem to Solve the Last One

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The discussion focuses on solving an inequality involving a function f(x) and determining the correct intervals where f(x) is less than zero. The user is struggling to identify the last interval needed for the solution. It is clarified that the values -2 and 3 cannot be included in the solution since f(x) must be strictly less than zero. The correct intervals are identified as (-∞, -2) and (3, ∞). The conversation emphasizes the importance of understanding strict inequalities in interval notation.
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Trying to get the last one, but not able to do it. What am I missing. I know that I can't but [-2,infinity] or [3,infinity] because for -2, and 3 y=0 and is not > 0. Any help appreciated.
 

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Is g(-2) > 0? No, so that part of the interval will be [math]( -\infty, -2)[/math].

-Dan
 
Also, because the question requires that f(x) be strictly less than 0, f(x)< 0 you cannot include x= -2 or x= 3. f(x)< 0 is true for (-\infty, -2)\cup (3, \infty).
 

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