- #1
Troubleshooting Line Tension: Expert Tips and Solutions
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SUMMARY
The forum discussion focuses on troubleshooting line tension in a physics problem involving forces and angles. The user calculates the horizontal and vertical distances, determining the angle θ as approximately 50.479 degrees. The tension T is calculated to be 1088.944 lb, and the reaction force R at point A is found to be 1385.924 lb. The discussion emphasizes the importance of free body diagrams and equilibrium equations in solving such problems.
PREREQUISITES- Understanding of basic physics concepts such as forces and equilibrium
- Familiarity with trigonometric functions, particularly tangent and sine
- Ability to construct and analyze free body diagrams
- Knowledge of reaction forces in static systems
- Study the principles of static equilibrium in physics
- Learn how to create and interpret free body diagrams
- Explore trigonometric identities and their applications in physics problems
- Review examples of tension calculations in cable systems
Students studying physics, engineers working with tension systems, and anyone involved in structural analysis or mechanics will benefit from this discussion.
- #2
tiny-tim
Science Advisor
Homework Helper
- 25,837
- 258
Hi drkidd22! 
Show us what you've tried, and where you're stuck, and then we'll know how to help!
Show us what you've tried, and where you're stuck, and then we'll know how to help!
- #3
drkidd22
- 59
- 0
So I have this so far trying to find Tbd.
It will be the same for Tbe as they are the same distance away from A.
It will be the same for Tbe as they are the same distance away from A.
- #4
drkidd22
- 59
- 0
distance on horizontal=√(18^2+18^2)=18*√2 ft
distance on vertical=21 ft
∴θ=angle in between pole & cable=tan-1(18*√2/21)=50.479 degree
Σall horizontal force=0
1680=2T sinθ
∴T=1088.944 lb
Σall vertical force =0
R=2T cosθ [R= reaction force at A ]
∴R=1385.924 lb
Not sure if it's correct
distance on vertical=21 ft
∴θ=angle in between pole & cable=tan-1(18*√2/21)=50.479 degree
Σall horizontal force=0
1680=2T sinθ
∴T=1088.944 lb
Σall vertical force =0
R=2T cosθ [R= reaction force at A ]
∴R=1385.924 lb
Not sure if it's correct
- #5
pongo38
- 739
- 27
How many components are there to the reaction at A (at most)? You ask if it is correct. But you could determine this yourself by recognising that there are at most 6 equilibrium equations for the whole thing...
- #6
drkidd22
- 59
- 0
There are three forces at A
Fx
Fz
Fy
Fx
Fz
Fy
- #7
pongo38
- 739
- 27
So have you calculated any of them so far?
(By the way your physicsp148.doc document has just one line and it is sloppy, or incorrect or inconsistent. If T is a force, why do the units have ft at the end?)
(By the way your physicsp148.doc document has just one line and it is sloppy, or incorrect or inconsistent. If T is a force, why do the units have ft at the end?)
- #8
pongo38
- 739
- 27
when you say "1680=2T sinθ ", exactly what free body diagram are you considering the equilibrium of?
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