MHB True or False Integral Calculus Question #2

Click For Summary
The discussion revolves around the statement that if $F(x)$ is an antiderivative of $f(x)$, then $F(2x)$ is an antiderivative of $f(2x)$. Participants analyze the derivative of $F(2x)$ and explore integration using substitution with $u = 2x$. The integration process reveals that $\int f(2x)dx$ equals $(1/2)F(2x)$, not $F(2x)$ itself. The conclusion drawn is that the initial statement is false, as the integration result differs from the expected antiderivative.
MermaidWonders
Messages
112
Reaction score
0
True or False: Let $F(x)$ be an antiderivative of a function $f(x)$. Then, $F(2x)$ is an antiderivative of the function $f(2x)$.
 
Last edited:
Physics news on Phys.org
What is the derivative of $F(2x)$? Or, perhaps more to the point, what do you get if you integrate $f(2x)$ using the substitution $u=2x,du=2\,dx$?
 
Kinda confused... how would you do that using substitution?
 
Try it and post your effort. :)
 
OK... Here's what I came up with... took me a while but I'm still kinda confused with myself. :(

Let $u = 2x$. Then $du/dx = 2$ --> $dx = du/2$.

$\int f(2x)dx$ then becomes $\int f(u)(du/2) = (1/2)f(u)du = (1/2)F(u) = (1/2)F(2x)$.
 
So I'm guessing that's false because $\int f(2x)dx \ne F(2x)$ but $(\frac{1}{2})F(2x)$, right?
 
MermaidWonders said:
OK... Here's what I came up with... took me a while but I'm still kinda confused with myself. :(

Let $u = 2x$. Then $du/dx = 2$ --> $dx = du/2$.

$\int f(2x)dx$ then becomes $\int f(u)(du/2) = (1/2)f(u)du = (1/2)F(u) = (1/2)F(2x)$.

That's right. Chain rule. :)

Excellent work!
 
Alright, thanks so much! :)
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
9
Views
4K
  • · Replies 36 ·
2
Replies
36
Views
6K