True or False: P-Dimensional Subspace and Basis for R^n

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SUMMARY

The statement that if H is a p-dimensional subspace of R^n and {v1,...vp} is a spanning set of H, then {v1,...vp} is automatically a basis for H is true. A p-dimensional subspace requires exactly p linearly independent vectors to span it, thus ensuring that any spanning set of p vectors is also a basis. This conclusion is rooted in the fundamental properties of vector spaces and linear independence.

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  • Understanding of vector spaces and subspaces
  • Knowledge of linear independence
  • Familiarity with spanning sets
  • Basic concepts of R^n and dimensionality
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  • Learn about the criteria for linear independence
  • Explore the concept of bases in vector spaces
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Students of linear algebra, educators teaching vector space concepts, and anyone seeking to deepen their understanding of subspaces and bases in R^n.

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Homework Statement



If H is a p-dimensional subsapce for R^n and {v1,...vp}
is a spanning set of H, then {v1,...vp} is automatically a basis for H.


True or False


Homework Equations



I am unsure of my answer.

The Attempt at a Solution



I am under the impression that this is true due to the fact that since the subspace is p-dimensional that {v1,...vp} is a basis because it must be linearly independent because this set spans p-dimensions thus needs p vectors.
 
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That's pretty much it. If you have p vectors that are linearly independent, and that span a subspace of dimension p, then these vectors are a basis for that subspace.
 

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