Truss Analysis using joints method 2D analysis

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SUMMARY

The forum discussion focuses on the analysis of a warren truss using the joints method for 2D analysis. The load applied is 2kN/m, resulting in a weight of 10kN per joint. The user calculated the force in member AB as 28.87 and established equilibrium equations for joint B, specifically net Fy = 0 and net Fx = 0. The discussion emphasizes the importance of identifying whether members are in tension or compression and notes the omission of a 5 kN force at the end joints, which does not impact the calculated member forces.

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  • Understanding of 2D truss analysis
  • Knowledge of equilibrium equations (net Fy = 0, net Fx = 0)
  • Familiarity with truss member forces (tension and compression)
  • Basic principles of static mechanics
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  • Study the effects of external loads on truss stability
  • Explore graphical methods for determining member forces in trusses
  • Investigate the impact of support conditions on truss behavior
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Civil engineers, structural analysts, and students studying mechanics of materials will benefit from this discussion, particularly those focusing on truss design and analysis.

FlorenceC
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Given a warren truss, where the load is 2kN/m so the weight per joint is 10kN, since the ends are supported by ground not truss, can anyone please verify my way of solving for the tension and compression at point B.
See attachment

Your help is greatly appreciated.

So I figured out that AB is 28.87 and with a FBD for joint B I ended up with the two equations:
net Fy = 0 and net Fx = 0
so, ABy=BCsin60 = 25
and ABx + BCcos60 = -BD = -28.87

Is this right?
 

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The magnitudes are OK, but be sure to indicate tension or compression. For example, is AB tension or compression?

Also note that you left out the 5 kN applied force at the end joints, which does not affect your result for the member forces noted.

Solve for BC.

I need a mirror...
 

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