The discussion revolves around a problem involving a horizontal truss that is symmetric and supported by two posts. Participants are tasked with determining the downward force exerted on each post, given the mass and length of the truss.
Some participants have provided guidance on using torque calculations to find the reaction forces at the posts. There is an ongoing evaluation of the calculated forces, with some participants suggesting adjustments for significant figures. Multiple interpretations of the problem setup are being discussed.
There is a note regarding the appropriateness of the support locations for the truss, indicating that the supports should ideally be at a joint, although this does not affect the calculations being discussed.
Yes, sum torques about one of the support posts = 0 to calculate the force reaction of the other post. Do the same thing in summing torques = 0 about the other post to calculate the force reaction of the first post. Check your work using Newton 1 (the equilibrium condition) in the y direction.amyparker30 said:
Almost spot on!amyparker30 said:
I say almost, because there should be just 2 significant figures in your answer. Implying Force right post = 83000 N, and F Left post = 64000 N. Or something like that. At least, get rid of the decimal points! 
