Truss Prob: finding the force in a member

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Discussion Overview

The discussion revolves around solving for the force in member HG of a truss structure using the method of sections. Participants explore the implications of a pulley system on the calculations and the overall force analysis within the truss.

Discussion Character

  • Homework-related
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant presents their calculations for the force in member HG and expresses uncertainty about the influence of the pulley system on their results.
  • Another participant questions the effect of the pulley on the truss and suggests considering equivalent forces at the end of the truss.
  • A different participant advises taking moments around point G to find the force in member DE and summing forces in both x and y directions to determine forces in members DG and GH.
  • Another participant emphasizes the need to identify the horizontal force at the top of the pulley in the free body diagram, questioning its theoretical and practical values.
  • A participant shares their updated workings for finding reactions at the supports, noting the impact of the pulley system on the external forces considered.
  • One participant comments on the reactions being correct but points out that the meanings of certain forces (F1, F2, F3) are not clearly defined.

Areas of Agreement / Disagreement

Participants express varying levels of understanding regarding the effects of the pulley system on the truss analysis. There is no consensus on the correct approach to account for these effects, and multiple viewpoints on how to proceed remain present.

Contextual Notes

Participants highlight potential limitations in their free body diagrams and calculations, particularly regarding the identification of forces and the assumptions made about the pulley system's influence.

Who May Find This Useful

Students and practitioners dealing with statics, truss analysis, and the effects of mechanical systems on structural forces may find this discussion relevant.

lazypast
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Homework Statement


The diagram is attached. I must solve using method of sections the force in member HG.



Homework Equations


ƩF(y) = 0, ƩF(x) = 0, ƩM = 0


The Attempt at a Solution



My hand-drawn pic shows the section.
Solving vertically, ƩF(y) = 0
F(DG)cos45 = 10
F(DG) = 14.1kN

Moments about E
10(2) + 2F(DG)cos45 + 2F(HG) = 0
Dividing by 2 and rearranging:
F(HG) = -10 - 14.1cos45 = -20kN



I don't think I'd have a problem if there wasn't a pulley system and I can only assume the reason I'm not getting the correct answer for F(HG) is because I'm not taking into account the effect the pulley has.

Can anyone advise a nudge in the right direct... ?
 

Attachments

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Well, what effect does the pulley have on the truss? Can the pulley be replaced by equivalent forces at the end of the truss?
 
Your free body diagram looks right. Now take a moment around G to find what member DE is. Next, sum the forces in x and y to find DG and GH.

Was I helpful to you with this? I really struggled with trusses in statics and now have a really good understanding of how to solve these problems.
 
In your free body diagram you need to identify the value of the horizontal force at the top of the pulley. What do think that is? (in theory, and in reality)
 
I have attached my workings out to find the reactions at the supports. Originally I was taking the total external forces at face value (i.e 10kN vertically down) but now I can see because the pulley system support is not connected to the structure there are extra forces.



Going back to the original FBD, I'll add and resolve with a horizontal force of 10kN in there, too. I've attached my workings out.
 

Attachments

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Reactions look good, but meanings of F1 F2 and F3 not well-defined.
 

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