1. The problem statement, all variables and given/known data A double loop circuit is shown in the figure below. The Emf x = 6.00 V and the Emf w = 19.00 V. Both are shown on the diagram. Calculate the power dissipated in the 6 Ω resistor located on the extreme right in the circuit. 2. Relevant equations V=IR, P=VI 3. The attempt at a solution I tried using superposition, where I replaced one battery with a short and solved for the voltage and current through the 6 ohm resistor, and the did the same by replacing the other battery with a short. The total current and voltage is the sum of the individual values. I plugged those final values into P=VI and got the wrong answer. Should this method work and I just did the work wrong or is there something I'm not aware of?