Trying to find the quotient of infinite sums

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SUMMARY

The discussion focuses on expressing the infinite sum \( \frac{(0+x+2x^2+3x^3+\ldots)}{1+x+x^2+x^3+\ldots} \) as a rational function. The denominator simplifies to \( \frac{1}{1-x} \), leading to the conclusion that the numerator must be \( \frac{1}{(1-x)(x-1)} \). The key to solving the problem lies in expressing the numerator as a function of \( x \), which can be achieved by factoring out \( x \) and applying integration techniques.

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demonelite123
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i am trying to re-express the following in terms of a rational function: \frac{(0+x+2x^2+3x^3+...)}{1+x+x^2+x^3+...}. i know that this is supposed to be \frac{1}{x-1} but I can't figure out how to do it.

I know the denominator is just \frac{1}{1-x}. so in order for this work out, the infinite sum which makes up the numerator should be \frac{1}{(1-x)(x-1)}. so my problem is figuring out how to express 0+x+2x^2+3x^3+... as a function of x. I have tried integrating/differentiating the series which didn't work and i haven't been able to figure out another way to do this.

can someone help me figure this out?
 
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Factor x out first, then integrate.
 
oh wow I am really getting rusty on my calculus. thanks for your reply!
 

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