- #1

Rhaen

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A 4.0 kg mess kit sliding on a frictionless surface explodes

into two 2.0 kg parts, one moving at 3.0 m/s, due north, and

the other at 5.0 m/s, 30 degrees north of east. (a) What is

the original speed of the mess kit. (b) How much kinetic

energy was added to the mess kit by the explosion?

I don't know exactly how to get started with this though I know that there would not be any potential energy so we would have the equation:

K_1 = K_2

(1/2)m_1(V^2) = (1/2)m_2(V^2)

But because the explosion adds kinetic energy to the equation through a non-conservative force we would have the equation:

K_1 + W_nc = K_2

(1/2)m_1(V^2) + W_nc = (1/2)m_2(V^2)

Is this correct in my understanding and if so, where would I go from here to get the original velocity? Thank you very much for your time.

-Rhaen-