Trying to get my head around tangent bundles

  • Context: Graduate 
  • Thread starter Thread starter mikeph
  • Start date Start date
  • Tags Tags
    Bundles Head Tangent
Click For Summary
SUMMARY

The discussion centers on the concept of tangent bundles in the context of integral transforms in R^n. Mike seeks clarity on how the tangent bundle can be visualized, particularly regarding the relationship between vectors on the unit sphere and vectors in R^n. It is established that the set of oriented lines in R^n is isomorphic to the tangent bundle of the (n-1)-sphere, TS^{n-1}, with each point on the tangent plane corresponding to a unique line. The mapping of the transform is suggested to be R^(n-1)^2, as each hyperplane in R^n can be described using n-1 scalars.

PREREQUISITES
  • Understanding of integral transforms in R^n
  • Familiarity with tangent bundles and their properties
  • Knowledge of vector spaces and isomorphism
  • Basic concepts of differential geometry
NEXT STEPS
  • Study the properties of tangent bundles in differential geometry
  • Learn about integral transforms and their applications in R^n
  • Explore the concept of isomorphism in vector spaces
  • Investigate the parametrization of hyperplanes and their relationship to tangent spaces
USEFUL FOR

Mathematicians, physicists, and students of differential geometry who are interested in understanding tangent bundles and their applications in higher-dimensional spaces.

mikeph
Messages
1,229
Reaction score
18
Hello,

Say you have a function f on the domain R^n, and an integral transform P which integrates f over all possible straight lines in R^n. I am lead to believe that the range of this is R^(2n), or a tangent bundle, which I am having MASSIVE problems visualising!

Am I right in saying the tangent bundle can be described by the multiplication of a vector on the unit sphere in R^n with a vector in R^n, ie. all points, then from each point, subtending all angles?

But surely this creates duplication? ie. for n=3, the line passing point (0,0,0) parallel to (1,0,0) must be the same as the line passing through (1,0,0) parallel to (1,0,0). So I am trying to picture a more "efficient" way to specify the range of this transform...

Is it completely described by all vectors in R^n perpendicular to each plane described by the vector on the unit sphere in R^n? How many are there per plane?

SO confused! But intrigued...

Thanks,
Mike
 
Physics news on Phys.org
The set of oriented lines in Rn is isomorphic to the tangent bundle of the n-1-sphere TS^{n-1}. At each point on a tangent plane of the unit sphere there is exactly one line intersecting orthogonally at that point. Choose one orientation of the line, say outwards, and this gives the isomorphism.
 
Last edited:
Thankyou,

Can I confirm, does isomorphism mean all the lines parallel to that line?

I would think the space which this transform maps to is R^(n-1)^2...

The reason being, each hyperplane in R^n can be described as perpendicular to a point on the unit sphere in R^n, requiring n-1 scalars. And then for each plane you can completely parametrise the perpendicular lines crossing it using R^(n-1), since the plane itself is parametrised this way.

So pick a direction, then pick a point on the plane perpendicular to this, and you get a unique straight line through R^n.

Is that correct?

Thanks,
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 26 ·
Replies
26
Views
7K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 9 ·
Replies
9
Views
8K
  • · Replies 3 ·
Replies
3
Views
2K