Turning Force vs. Accelerating Force

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Applying a force through the center of gravity of a sphere results in linear acceleration according to F=ma, while a force applied off-center creates a turning force described by T=F*d. Even when a force does not act through the center of mass, Newton's second law remains applicable, allowing for the calculation of overall acceleration. It is noted that applying a force at the edge of an object can still produce the same linear acceleration as a force through the center, though it may also induce rotation. The discussion emphasizes the distinction between linear and angular acceleration, highlighting that forces causing rotation require greater power due to the additional work involved.
thepopasmurf
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If I have a sphere (or another 3D object) and I apply a force to it through the centre of gravity, it will accelerate according to F=ma
If I apply a force to the sphere which doesn't act through the centre of gravity, I apply a turning force according to T=F*d

How do you figure out how much the body as a whole accelerates when you apply a turning force to it?
 
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thepopasmurf said:
If I have a sphere (or another 3D object) and I apply a force to it through the centre of gravity, it will accelerate according to F=ma
If I apply a force to the sphere which doesn't act through the centre of gravity, I apply a turning force according to T=F*d

How do you figure out how much the body as a whole accelerates when you apply a turning force to it?
Simply apply Newton's second law and well as the rotational equation of motion. Newton's second law is still valid even if a the force is not applied through the COM of the body.
 
But does applying a force to the edge of an object have the same accelerating effect?
I imagine that a glancing blow won't move an object as much as a force acting through the COM
 
thepopasmurf said:
But does applying a force to the edge of an object have the same accelerating effect?
Yes, it does. It seems a bit counterintuitive, but that's how things work. This has been very well tested -- e.g., in spacecraft .
 
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That's correct.
 
thepopasmurf said:
That is counter-intuitive. So, on this diagram, all three equal magnitude forces will accelerate the block the same amount in the same direction? (And two will cause it to rotate?)http://img142.imageshack.us/img142/32/forcesre1.th.jpg
The forces are the same, but not the power. The forces that that cause rotation (angular acceleration) have to be applied at a faster rate of acceleration, at faster speed, and longer distance, so more work (force times distance) is done for the forces that cause rotation, which is why the power is higher, and the total energy, linear and angular, is increased more by the forces that also cause rotation (angular acceleration).
 
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How is that thread related at all? That thread is about particles: Point masses. This thread is about what happens to a non-point mass object subject to a force that does not pass through the object's center of mass.
 
  • #10
This question is related to my above question. Friction doesn't act through the center of mass, but then where on a free body diagram do you place the force which keeps the object (say a block) from spinning?
 

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