Twins Separated at Birth: Do Ages Match?

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SUMMARY

The discussion centers on the relativistic effects experienced by twins separated at birth, specifically focusing on Twin B's journey at a velocity, V, while Twin A remains on Earth. Twin A emits light signals on each birthday, and the calculations reveal that Twin B, upon returning, will have aged less than Twin A due to time dilation effects. The relationship between the events in different frames is established using the equation c = x2 / (t2 - t1), leading to the conclusion that t2 = (ct1) / (c - V) in the Earth frame. A space-time diagram is suggested for a clearer understanding of the scenario.

PREREQUISITES
  • Understanding of special relativity principles
  • Familiarity with time dilation and twin paradox concepts
  • Knowledge of light signal propagation and its implications
  • Ability to construct and interpret space-time diagrams
NEXT STEPS
  • Study the implications of the twin paradox in special relativity
  • Learn how to construct and analyze space-time diagrams
  • Explore the mathematical derivation of time dilation formulas
  • Investigate the effects of varying velocities on time perception
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This discussion is beneficial for physics students, educators, and anyone interested in the applications of special relativity, particularly in understanding time dilation and the twin paradox scenario.

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Homework Statement


Twins are separated at birth on earth. Twin B travels in a straight line back and forth at a velocity, V. According to twin A, who stays on earth, twin B travels away for 10 years, and then back toward Earth for ten years.

They send light signals to each other at every birthday each one celebrates. When do they receive another's signals and does each count agree with their ages upon return?

Homework Equations





The Attempt at a Solution


Event 1: A emits a pulse
Event 2: Y receives the pulse

Event 1, in earth-frame: (t[itex]_{1}[/itex], 0)
Event 1, in moving frame of B: (t[itex]^{'}_{1}[/itex], -Vt[itex]_{1}[/itex])

Event 2, in earth-frame: (t[itex]_{2}[/itex], Vt[itex]_{2}[/itex])
Event 2, in moving frame of B: (t[itex]^{'}_{2}[/itex], 0)

This gives me both events in each coordinate system. They can be related by the expression c=[itex]\frac{x_{2}}{t_{2}-t_{1}}[/itex]. After substituting x[itex]_{2}[/itex]=Vt[itex]_{2}[/itex] and simplifying, we have t[itex]_{2}[/itex]=[itex]\frac{ct[itex]_{1}[/itex]}{c-V}[/itex]. This gives the relationship in the earth-frame.

Now how do I get the relationship in the moving frame?
 
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You can get an understanding of what is happening by constructing the space-time diagram. Try this description.
 

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