1. The problem statement, all variables and given/known data The positive terminals of two batteries with emf's of V_1 and V_2, respectively, are connected together. It is V_2>V_1. The circuit is completed by connecting the negative terminals. If each battery has an internal resistance r, what is the rate with which electrical energy is converted to chemical energy in the smaller battery? Answer: (V_2-V_1)*V_1/r 2. Relevant equations P=IV V=IR 3. The attempt at a solution From what I was trying is that I=(V_2-V_1)/(2r) and then the voltage difference is V_1, so I was getting P= (V_2-V_1)*V_1/(2r), what am I doing wrong that I'm off back a factor of two.