Two blocks, as shown below, are connected by a string of negligible mass passing over a pulley of radius 0.225 m and moment of inertia I. The block on the frictionless incline is moving up with a constant acceleration of 1.97 m/s2 on an angle of 35.1 degrees.
m1 = 15.4 kg
m2 = 19.5 kg
A set up of the blocks and incline can be seen below, but the values above are used in all calculations
(a) Determine the tensions in the two parts of the string.
(b) Find the moment of inertia of the pulley.
The Attempt at a Solution
K, so I solved for T2 but I am unable to solve T1.
For T2, I set m2g-T2 = m2a
(19.5)(9.8) - T2 = (19.5)(1.97)
T2 = 152.6 N
For T1, I found the x component of acceleration to be 1.97cos35.1 = 1.612 m/s^2
From there I though T1 would be mgsin35.1 but that was wrong. I know I need the acceleration to find T1 (at least I think so) because the question specifically stated the acceleration so it must be used to equate T1 with ma or something like that. Please help!
As for B, I know the moment of inertia of a pulley to be 1/2Mr^2.
Rotational Kinetic energy = 1/2Iw^2 ( I don;t know if this is needed to solve the question)
Please, some guidance for both of the questions would be greatly appreciated!