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## Homework Statement

Two blocks, as shown below, are connected by a string of negligible mass passing over a pulley of radius 0.225 m and moment of inertia I. The block on the frictionless incline is moving up with a constant acceleration of 1.97 m/s2 on an angle of 35.1 degrees.

m1 = 15.4 kg

m2 = 19.5 kg

A set up of the blocks and incline can be seen below, but the values above are used in all calculations

http://www.webassign.net/pse/p10-71alt.gif

(a) Determine the tensions in the two parts of the string.

T1:

T2:

(b) Find the moment of inertia of the pulley.

## Homework Equations

## The Attempt at a Solution

K, so I solved for T2 but I am unable to solve T1.

For T2, I set m2g-T2 = m2a

(19.5)(9.8) - T2 = (19.5)(1.97)

T2 = 152.6 N

For T1, I found the x component of acceleration to be 1.97cos35.1 = 1.612 m/s^2

From there I though T1 would be mgsin35.1 but that was wrong. I know I need the acceleration to find T1 (at least I think so) because the question specifically stated the acceleration so it must be used to equate T1 with ma or something like that. Please help!

As for B, I know the moment of inertia of a pulley to be 1/2Mr^2.

Rotational Kinetic energy = 1/2Iw^2 ( I don;t know if this is needed to solve the question)

Please, some guidance for both of the questions would be greatly appreciated!