Two blocks sliding down an incline

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Homework Help Overview

The problem involves two packages sliding down a 20-degree ramp, with specific masses and coefficients of friction provided. The original poster seeks to determine the time it takes for package A to reach the bottom of the ramp after starting from rest.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster presents free body diagrams and equations of motion for both packages. Some participants question the sign conventions used in the force equations and suggest revisiting the free body diagrams to clarify the direction of forces.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's approach. There is an indication that the original poster is encouraged to reassess their free body diagrams and force balance, but no consensus or resolution has been reached yet.

Contextual Notes

The original poster expresses uncertainty about their calculations and seeks clarification on the errors in their approach. There is an emphasis on the importance of correctly identifying the direction of forces in the free body diagrams.

oneamp
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Homework Statement


The figure shows two packages that start sliding down a 20 degree ramp from a rest a distance d=6.6m along the ramp from the bottom. Package A has a mass of 5.0kg and a coefficient of friction 0.20. Package B has a mass of 10kg and a coefficient of friction of 0.15. How long does it take package A to reach the bottom?

Illustration shows A closer to the ground on the ramp, with B directly behind (and in contact with) it.


Homework Equations





The Attempt at a Solution



I made a free body diagram for each block.

A
---
m = 5kg
mu_k = 0.20
f_k = 9.21 N
n = 46.04 N
F_G_x = -16.76 N
F_G_y = -46.04 N

B
---
m = 10kg
mu_k = 0.15
f_k = 13.82 N
n = 92.1 N
F_G_x = -33.52 N
F_G_y = -92.1 N

------
Third law stuff:
F_(a on b) = F_(b on a) = simply 'F' below.
a_a = a_b (acceleration constraint)

---
sum of x for A: -7.55 + F = ma = (5)(a)
for B: -19.7 + F = ma = (10)(a)

solve the system of equations:

a = -2.43 m/s^2

kinematics:

t = 2.335

But -- my answer is wrong. Why?

Thank you
 
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oneamp said:
sum of x for A: -7.55 + F = ma = (5)(a)
for B: -19.7 + F = ma = (10)(a)
you have not taken proper sign with F.

Draw and show, your free body diagram. If you check FBD, it will become clear that the direction of F is different in both the case but you have taken same direction for both mass. Balance forces again to clearly see the mistake.
 
I will try it out, thank you
 
oneamp said:
I will try it out, thank you

okay!
 

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