Two bodies moving from point A

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SUMMARY

The discussion revolves around a physics problem involving two bodies moving from point A with different acceleration patterns. The first body accelerates by 6 m/min every minute starting from 3 m/min, while the second body starts 5 minutes later at 54 m/min, increasing by 3 m/min each subsequent minute. The user initially attempts to apply the distance formula but realizes that the increasing speed of the first body cannot be treated as constant acceleration. The correct approach involves recognizing the arithmetic progression of distances traveled by each body over time.

PREREQUISITES
  • Understanding of kinematics, specifically the equations of motion.
  • Familiarity with arithmetic progression concepts.
  • Basic algebra skills for solving equations.
  • Knowledge of how to set up equations based on motion problems.
NEXT STEPS
  • Study the concept of arithmetic progression in motion problems.
  • Learn how to apply kinematic equations to non-uniform acceleration scenarios.
  • Practice solving similar physics problems involving multiple moving bodies.
  • Explore the implications of starting times and initial velocities in motion equations.
USEFUL FOR

This discussion is beneficial for students studying physics, particularly those tackling motion problems, as well as educators looking for examples of common misconceptions in kinematics.

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Homework Statement



One body starts moving from point A so that in first min it goes 3 m/min, and in every next minute it goes 6 m more that in the minute before. Another body starts moving from point A 5 minutes later, going 54 m/min in the first minute and in every other minute 3 m more that in the minute before. After how many minutes have the bodies traveled the same distance? (Time starting after the second body starts its movement.)

Homework Equations



s=v0t+at2/2

where s - distance
v0 - initial velocity
a - acceleration
t - time

The Attempt at a Solution



I already know how you can solve this using arithmetic progression. But what I can't understand is why doesn't the distance equation from physics apply in this. It ought to!

So what I did was this:

s1=s2

s1=3(t+5)+6(t+5)2/2
s2=54t+3t2/2

3(t+5)+6(t+5)2/2=54t+3t2/2

t=1,5t2-21t+75,

which doesn't work out. What am I doing wrong here?

Thanks in advance,
fawk3s
 
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Ok, I think I figured it out now. I guess you can't take those "goes 6 m more in the next minute" as an acceleration.
This thinking made my head hurt :(
 

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