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Two capacitors in parallel: potential difference/energy
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[QUOTE="space-time, post: 5575746, member: 505645"] I don't know for sure what remains constant and what evens out, but my educated hypothesis leads me to believe that the total charge on the capacitors will balance out so that the positive and negative plates have equal, but opposite charges. Is this correct? As for what remains constant, does the equivalent capacitance remain constant? If my assertions are correct, then since the total charge on the capacitors to begin with was 1.92 * 10[SUP]-4[/SUP] C (I calculated this), and since the equivalent capacitance is 1.6 * 10[SUP]-5[/SUP] F, I believe that if I divide my charge by 2 (so that both capacitors have the same amount of charge on them) and use V = Q/C, then I can do (9.6 * 10[SUP]-5[/SUP]) / (1.6 * 10[SUP]-5[/SUP]) = 6 V (Note that the 9.6 * 10[SUP]-5[/SUP] came from dividing my total charge by 2) Is 6 V the correct answer for (a) by my process? Also, are you saying that I got the right answer for (b), and that the answer for the first half of (b) is the same as that of the second? [/QUOTE]
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Two capacitors in parallel: potential difference/energy
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