Two chambers are interconnected by a valve

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SUMMARY

The discussion centers on the thermodynamic principles governing interconnected chambers with a valve. Participants assert that if there is no change in internal energy, the temperature of the chambers will equilibrate to match the surrounding environment. This conclusion is based on the laws of thermodynamics, specifically the concept of thermal equilibrium, which dictates that systems in contact will reach the same temperature over time. The implications for practical applications in thermal management systems are significant.

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Fatima Hasan
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Homework Statement
Two chambers, 10 m3 each, are interconnected by a valve, as shown in the figure, with one chamber containing air at 2500 kPa and 287°C and the other chamber is evacuated. The valve is now opened and the air reaches a mechanical equilibrium and a thermal equilibrium with the surroundings at 15°C. Determine (a) the final pressure, (b) the final temperature of air, (c) the total change in internal energy, and (d) the amount of heat transfer.
Relevant Equations
Here is my work :
State 1 :
A
V1A = 10 m^3
P1A = 2500 kPa
T1A = 560 K
m1A = P1A * V1A / (T1A *R)
m1A = 155.5 kg
B
V2A = 10 m^3
m2A = 0 kg
State 2 :
T = 15+273 = 288 K , and that's the final temperature ? ( not sure about that , because it's given and the question in part (b) asks to get the final temperature )
m2 = m1A + m2A
m2 = 155.5 kg
V2 = V1A + V2A
V2 = 10 + 10 --> = 20 m^3
P2 = m2 * R * T / V2
P2 = 642.6504 K Pa ( the final pressure )
Since there are no heat and work interactions ,
c) = 0
d) = 0
Could someone check my answer please ?
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If there was zero change in internal energy, can you explain the temperature change to be "equal to the surroundings"?
 

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