Two charged particles moving towards each other

Click For Summary
SUMMARY

The discussion focuses on calculating the distance of closest approach for two protons moving towards each other with initial speeds of 1.5 x 10^6 m/s. The solution involves applying the law of conservation of energy, where the total kinetic energy of both protons is converted into potential energy at the closest point of approach. The participants confirm that since both protons have equal mass, they will stop simultaneously, reinforcing the conservation of energy principle in this context.

PREREQUISITES
  • Understanding of classical mechanics and conservation of energy principles
  • Familiarity with electrostatic potential energy calculations
  • Basic knowledge of particle physics, specifically proton behavior
  • Ability to perform calculations involving kinetic energy
NEXT STEPS
  • Study the conservation of energy in electrostatic systems
  • Learn about potential energy between charged particles
  • Explore the concept of closest approach in particle physics
  • Review calculations involving kinetic energy and momentum
USEFUL FOR

Physics students, educators, and anyone interested in understanding particle interactions and energy conservation in electrostatics.

Nivlac2425
Messages
53
Reaction score
0

Homework Statement


Two protons are moving directly towards each other. When they are very far apart, their initial speeds are 1.5 x 10^6 m/s. What is the distance of closest approach?


Homework Equations





The Attempt at a Solution


I know how to do this problem when one of the charges are fixed by using the law of conservation of energy. But in this problem, they are both moving towards each other, so is it possible to still use energy? In what manner?

Thanks everyone for helping out! =)
 
Physics news on Phys.org
If they are equal mass then they will both stop at the same time right?

So won't the total kinetic energy then be bound into potential energy between the two particles?
 
That's right, I see now. I was thinking of it in a somewhat too traditional way, but now I get it. Thanks very much! For this and my other question too!

=)
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 1 ·
Replies
1
Views
855
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 24 ·
Replies
24
Views
2K
Replies
6
Views
2K