Two charges located along x. Find all values?

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SUMMARY

The discussion focuses on determining the values of an unknown charge located at "+3a" along the x-axis, given a known charge Q at "-a" and the requirement that the net electric field at the origin equals 2Ke(Q/a²). The equations derived are Ke(Q/a²)i - Ke(q/9a²) = 2Ke(Q/a²)i for a negative charge and Ke(Q/a²)i - Ke(q/9a²) = -2Ke(Q/a²)i for a positive charge. The analysis concludes that if the charge at the origin is considered positive, the unknown charge must be -9Q, while if negative, the charge must be 27Q, indicating it is a positive charge.

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Homework Statement


The first one has charge Q is at "-a" from origin the second is at "+3a" which is an unknown charge.What are the values for unknown charge if at the origin the net electric field they produce with magnitude 2Ke(Q/a2)

Homework Equations


Ke (Q/a2)i - Ke(q/9a2)=2Ke(Q/a2)i
if charge is negative
or
if the charge is positive
Ke (Q/a2)i - Ke(q/9a2)=-2Ke(Q/a2)i

The Attempt at a Solution


The question is how to choose signs for equation.
Attempt:
Assuming charge one is pointed towards the origin along x-axis so the sign will be "+i" and the second charge is pointed towards the origin in the negative x direction so tthe sign will be "-i".
Two possible values are at the origin: "+" or "-" 2Ke(Q/a2) .
If you choose "+" at the origin the answer will be -9Q. And for case chosen "-" sign in the origin, the answer will be 27Q so the particle has positive charge.
I wondering if this is the explanation?
 
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Correct.
 
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