Two conducting planes, one grounded one has a surface charge

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SUMMARY

The discussion centers on calculating the electric field and potential between two conducting planes, one with a surface charge density σ and the other grounded, positioned parallel to each other. The electric field just above the grounded plane is determined using the equation E = σ/(2ε₀), where ε₀ is the permittivity of free space. The surface charge density on the top plane is described as σcos(λx), indicating a sinusoidal variation. The method of images is suggested as a potential approach to solve the problem, particularly if both planes are infinite conductors.

PREREQUISITES
  • Understanding of electrostatics and electric fields
  • Familiarity with Gauss's Law and its applications
  • Knowledge of surface charge density and its effects on electric fields
  • Experience with the method of images in electrostatics
NEXT STEPS
  • Study the method of images for solving electrostatic problems
  • Learn about the implications of sinusoidal charge distributions on electric fields
  • Review Gauss's Law and its application to infinite planes
  • Explore the concept of potential difference in electrostatic systems
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Students and professionals in physics, particularly those focusing on electrostatics, electrical engineers, and anyone involved in theoretical physics or electrical field calculations.

SU403RUNFAST
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Homework Statement



The plane with surface charge sigma lies in x-z plane at y=0, parallel to it at y=a there is a grounded plane. What is the field just above the bottom plane, find the potential between the planes

Homework Equations


discontinuity E=sigma/epsilon, V=Qd/Aepsilon take the gradient I can find V, what is E

The Attempt at a Solution


I know that for an infinite plane just above or below the E field is sigma over epsilon naught. The sigma in this question on the top plane is sigmacos(lambdax) so it depends on x, is sinusoidal. is E sigma/epsilon and i just plug in the sigma given? Or do i do the method of images
 
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SU403RUNFAST said:

Homework Statement



The plane with surface charge sigma lies in x-z plane at y=0, parallel to it at y=a there is a grounded plane. What is the field just above the bottom plane, find the potential between the planes

Homework Equations


discontinuity E=sigma/epsilon, V=Qd/Aepsilon take the gradient I can find V, what is E

The Attempt at a Solution


I know that for an infinite plane just above or below the E field is sigma over epsilon naught. The sigma in this question on the top plane is sigmacos(lambdax) so it depends on x, is sinusoidal. is E sigma/epsilon and i just plug in the sigma given? Or do i do the method of images
Isn't the field just above or below an infinite plane sigma over two epsilon naught?

Gauss says E * a is sigma*a over epsilon naught. But we have to close the pillbox on both sides of the sheet, so E * a is actually 2Ea. The sigma*a/(2a*eps0) = E, and the field is sig over two E naught. Outside a conductor the two would drop out, I believe. But if it's just a sheet...
 
SU403RUNFAST said:
I know that for an infinite plane just above or below the E field is sigma over epsilon naught.
Yes, at any point just outside the surface of any conductor, the electric field is perpendicular to the surface and has a magnitude ##|E| = |\sigma|/\epsilon_0## (assuming electrostatic conditions).

The sigma in this question on the top plane is sigmacos(lambdax) so it depends on x, is sinusoidal. is E sigma/epsilon and i just plug in the sigma given?

Did you mean to say that this is ##\sigma## on the top surface of the plane at ##y = 0##? If so, I would agree.

EDIT: However, I don't think the bottom plane can have such a space-varying charge density if the plane is a conductor. Are you sure both planes are conductors? Also, are they infinite planes?
 
Last edited:

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