- #1

JackPunchedJi

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## Homework Statement

The potential is of course defined by: V = 1/2m(Omegax)x^2 + 1/2m(Omegay)y^2

## Homework Equations

Generally when doing a harmonic oscillator we find that in two dimensions the energy is just:

(Nx+Ny+1)hbarOmega is the energy.

How does this change when the Omegax and Omegay are not equal?

## The Attempt at a Solution

Do we simply get the energy as...

E = (Nx+1/2)hbarOmegax + (Ny+1/2)hhbarOmegay ?

That would seem logical, but would like the clarification.