Two Dimensional Kinematics Projectile Motion

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Jetsgirl
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Homework Statement



Hi, I am doing a projectile motion lab for two dimensional kinematics. After completing the procedure of the lab, I have 3 graphs where

Y vs. X has a slope of y = -0.0037x2 + 0.9169x + 0.2684


X vs. T has a slope of y = 373.95x + 3.4011


Y vs. T has a slope of y = -505.11x2 + 328.29x + 3.5949

From the graphs, I have to figure out

ay (cm/s^2)
vx (cm/s)
v0y (cm/s)
angle (degrees)




Homework Equations



ax (t) = 0
ay (t) = -g
vx (t) = v0x
vy (t) = voy + ayt

x(t) = x0+v0xt
y(t) = y0+v0yt+1/2ayt^2

Change in angle = (vy^2*change in vs^2 + vx^2 + change in vy^2)/(vx^2 + vy^2) * (180/pi)

The Attempt at a Solution



vx = 373.95 +/- 3.4011

But for voy, and ay, the equations say that I need to use a specific time to find the answer, which I do not have according to the graphs.

Any suggestions on how to obtain the other two (ay, v0y) would be greatly appreciated.
From there I know I can find the angle by plugging all the components into the "change in angle" equation given above.

Thanks all.
 
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You gave the equation for y(t):
[tex]y(t) = y_0+v_{y0}t+\frac{1}{2}a_y t^2[/tex]
You also said that the equation you found for y(t) was (I assumed those should have been 't's not 'x's):
[tex]y = -505.11t^2 + 328.29t + 3.5949[/tex]
So how can you find v0y and ay?