1. The problem statement, all variables and given/known data A shot-putter throws the shot with an initial speed of 11.2 m/s from a height of 5.00 ft above the ground. What is the range of the shot if the launch angle is a) 20 degrees, b) 30 degrees, or c) 40 degrees? 2. Relevant equations y = 1/2 gt^2 x = vt R= Range R = (v0^2/g)sin2(theta) ? 3. The attempt at a solution For a) 20 degrees: t = sqrt(2y/g) t = 1.01s x = (11.2 m/s)(1.01s) = 11.3 m b) R= [(11.2m/s)^2 /9.81 m/s^2] (2sin(30)) R= 12.78 m (this is incorrect..) c) R= [(11.2 m/s)^2 /9.81 m/s^2] (2sin(40)) R = 16.48 m (this is also incorrect) I don't really understand how I should approach this problem, or which equations I should use. The range equation is not working for me. I can't repeat the steps from part a because they did not include the angle in the first place.. I appreciate any help given.