An artillery shell is fired at mach 2 at an enemy encampment located at a range of 1700m. The initial position of the shell is 72 meters below the encampment, and is aimed at an angle θ.
Solve the problem for θ.
We can get the following variables/data from this:
Range = 1700m
Vertical displacement = 72m
Initial speed = 800m/s
From this I derived these equations:
1700=800cosθt (d = r*t)
72 = 800sinθt - 4.905t^2 (d = Vi*t + 1/2a*t^2)
2 equations with two unknowns. Problem is, I don't know how to solve them.
The Attempt at a Solution
What I attempted was solving for t in the first equation, giving me t = (1700)/(800cosθ). Plugging this back into the second equation, I get 72 = 800sinθ(1700/800cosθ) - 4.905(1700/800cosθ)^2
From here, I got crazy solutions that ended up putting me at 89.5772 degrees for θ, which is incorrect. How can I correctly solve this?