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An aircraft launches a bomb. The plane is playing upward at an angle of 55 degrees to the horizon. When the bomb is launched, the plane has a speed of 745 km/h. at the time of aluch, the bomb is 8750 m above the ground.

-how long does it take the bomb to reach its highest point

-how high does the bomb go from where it was launched

-how much time until it hits the ground

-how far horizontally does it travel

2. Homework Equations [/b]

The kinematic equations

3. The Attempt at a Solution [/b]

1.) convert 745km/hr to 207m/s

cos(55)=vx/207m/s, 119m/s=vx

sin(55)=vy/207m/s, 170m/s=vy

Δv=at, t=17s

2) I have no clue how to do

maybe y vy-1/2gt^2

3) No idea how to approach

4) d=vt

7497m