Two dimensional projectile question-Check answers and help

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SUMMARY

The discussion centers on a physics problem involving projectile motion, specifically the launch of a bomb from an aircraft at a 55-degree angle with an initial speed of 745 km/h (converted to 207 m/s). Key calculations include determining the time to reach the highest point (17 seconds), the horizontal distance traveled (7497 m), and the maximum height achieved. Participants emphasize the importance of using kinematic equations and correctly applying gravitational acceleration in their calculations.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Ability to convert units (e.g., km/h to m/s)
  • Knowledge of trigonometric functions (sine and cosine)
  • Familiarity with projectile motion concepts
NEXT STEPS
  • Review kinematic equations for projectile motion
  • Practice unit conversion techniques for speed
  • Study the application of trigonometric functions in physics
  • Explore detailed examples of projectile motion problems
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Students studying physics, particularly those focusing on projectile motion, as well as educators looking for examples of real-world applications of kinematic equations.

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1. Homework Statement [/b]

An aircraft launches a bomb. The plane is playing upward at an angle of 55 degrees to the horizon. When the bomb is launched, the plane has a speed of 745 km/h. at the time of aluch, the bomb is 8750 m above the ground.

-how long does it take the bomb to reach its highest point
-how high does the bomb go from where it was launched
-how much time until it hits the ground
-how far horizontally does it travel

2. Homework Equations [/b]

The kinematic equations


3. The Attempt at a Solution [/b]

1.) convert 745km/hr to 207m/s

cos(55)=vx/207m/s, 119m/s=vx

sin(55)=vy/207m/s, 170m/s=vy

Δv=at, t=17s

2) I have no clue how to do

maybe y vy-1/2gt^2

3) No idea how to approach

4) d=vt

7497m
 
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megustaramen said:
1. Homework Statement [/b]

An aircraft launches a bomb. The plane is playing upward at an angle of 55 degrees to the horizon. When the bomb is launched, the plane has a speed of 745 km/h. at the time of aluch, the bomb is 8750 m above the ground.

-how long does it take the bomb to reach its highest point
-how high does the bomb go from where it was launched
-how much time until it hits the ground
-how far horizontally does it travel

2. Homework Equations [/b]

The kinematic equations3. The Attempt at a Solution [/b]

1.) convert 745km/hr to 207m/s

cos(55)=vx/207m/s, 119m/s=vx

sin(55)=vy/207m/s, 170m/s=vy

Δv=at, t=17s
I think you did this right, but it would help if you showed all your work. What are you using for the acceleration of gravity?
2) I have no clue how to do

maybe y vy-1/2gt^2
Sounds good, but make sure you get the equation right.
3) No idea how to approach
What does "hit the ground" translate into mathematically?
4) d=vt

7497m
Where did this number come from?
 

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