Two E. Bound RR Cars Collide: What Happens Next?

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SUMMARY

The collision of two railroad cars, one weighing 20,000 lbs traveling at 5 ft/sec and the other weighing 40,000 lbs at 7.81 ft/sec, results in both cars coupling together and moving with a common velocity. Using the principle of conservation of momentum, the total momentum before the collision is calculated as the sum of the individual momenta of both cars. The combined mass after the collision is 60,000 lbs, and the final velocity can be determined by dividing the total momentum by this combined mass, resulting in a velocity of approximately 6.5 ft/sec in the easterly direction.

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A railroad car that weighs 20,000 lbs. is traveling eastward with a velocity whose magnitude is 5 ft./sec. A second car, on the same track, that weighs 40,000 lbs. is also traveling in an easterly direction with a velocity of 7.81 ft./sec. When the cars collided, they became coupled together and then both cars moved with the same velocity. If friction between the cars and the rails is neglected, what were the magnitude and the direction of the velocity of the cars after the collision?
 
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You can use conservation of momentum. Momentum in a closed system is always a constant. To calculate momentum use p = mv (p = momentum, m = mass, v = velocity). As they are coupled together after the collision, you are just taking the combined mass and using the momentum from before the collision (work out the momentum of each car and add them) to work out v.
 


wow thanks for your big help
 

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