Two masses connected via pulley: find acceleration

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SUMMARY

The discussion centers on calculating the acceleration of two connected masses, A (1.6 kg) and B (2.4 kg), over a frictionless pulley. It is established that both masses share the same acceleration due to their connection via a light string. The correct equations of motion are derived as T - 16 = 1.6a for mass A and T - 24 = 2.4a for mass B. The final acceleration is determined to be 10 m/s², with tension T calculated to be zero, indicating a need for careful consideration of the system's forces and directions.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Knowledge of tension in a string system
  • Familiarity with simultaneous equations
  • Concept of acceleration in connected systems
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  • Study the principles of Newton's Laws in detail
  • Learn about tension forces in pulley systems
  • Explore solving simultaneous equations in physics problems
  • Investigate the effects of friction in pulley systems
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Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators seeking to explain concepts related to pulleys and connected masses.

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Homework Statement


Two masses A and B, and of mass 1.6kg and 2.4kg respectively are connected by a light string which passes over a frictionless pulley. Calculate the acceleration of the 1.6kg mass.

Homework Equations


The Attempt at a Solution


To get started I must know whether the two masses both have the same acceleration. Is that true? I know the tension of the system is the same.

Assuming it's true I get a simultaneous equation that looks like
16-T=1.6a
24-T=2.4a

which works out for a=10m/s^2 and T=0 which is a bit fishy. But if a is different for each mass than there are 3 variables but only two equations.
 
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The two masses have the same acceleration (they are connected by a string!) The smallest mass will move upwards, so its resultant force will be T-16, hence your first equation should read T-16=1.6a
 
I see. The system should have a predetermined positive, negative direction. It's not the case that upwards is always + and downwards always - in this pulley problem.
 

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