Two masses on an inclined plane with a massless pulley

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Homework Help Overview

The problem involves two masses, one on an inclined plane and the other hanging, connected by a massless string over a frictionless pulley. The inclined mass has specific coefficients of friction and the goal is to determine the minimum mass that will not slip and the acceleration when nudged.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate the minimum mass and the resulting acceleration but encounters discrepancies in their results. Some participants question the assumptions regarding tension and acceleration, suggesting a need for a system of equations to solve for both tension and acceleration.

Discussion Status

Participants are actively discussing the equations involved and exploring the relationships between tension, friction, and acceleration. Guidance has been offered regarding the need to account for forces acting on both masses, indicating a productive direction in the discussion.

Contextual Notes

There is a mention of specific coefficients of friction and the angle of the incline, which may influence the calculations. The original poster's results suggest potential misunderstandings in applying the equations correctly.

JefeNorte
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Homework Statement


A block of mass m resting on a 20 degree slope. The block has coefficients of friction mu_s =0.80 and mu_k =0.50 with the surface. It is connected via a massless string over a massless, frictionless pulley to a hanging block of mass 2.0 kg.

What is the minimum mass m that will stick and not slip?

If this minimum mass is nudged ever so slightly, it will start being pulled up the incline. What acceleration will it have?

Homework Equations


T-f_k-(mg*sin(theta))=m*a
f_k=u_k*(mg*cos(theta))

The Attempt at a Solution


I completed the first part of the problem and determined that the minimum mass is 1.829 kg. I calculated the tension on the rope by multiplying the mass of the hanging block by 9.8. But when I plug these values into the equation I keep getting 2.76 m/s^2 which is not the correct answer. Is there something wrong with my equations or the tension value?
 
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The tension in the rope is only equal to the weight of the hanging block if the objects aren't accelerating. You need to write the sum of the forces = ma for each object, where the sum of the forces includes the unknown tension T. Then you have two equations and two unknowns and you solve for T and a.
 
Do you mean like T-(u_k*(mg*cos(theta)))-(mg*sin(theta))=m*a?
 
I mean something exactly like that.
 

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