- #1
crazyog
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Homework Statement
Two boxes are connected to each other as shown. The system is released from rest and the 1.00 kg box falls through a distance of 1.00 m. The surface of the table is frictionless. What is the kinetic energy of box B just before it reaches the floor?
Homework Equations
I believe you should be using an equation such as Ei=Ef
kinetic energy - (1/2)mv^2
and potential energy - mgy
The Attempt at a Solution
so Ei = (1/2)mvi^2 + (1/2)mv^2 + mgy +mgy
= (1/2)(3)(0)^2 + (1/2)(5)(0^2) +(3)(9.8)(0) + (1)(9.8)(1)
Ef = (1/2)mvi^2 + (1/2)mv^2 + mgy +mgy
= (1/2)(3)(vi)^2 + (1/2)(5)(vi^2) +(3)(9.8)(0) + (1)(9.8)(.01)
the velocity would be the same for each since they are connected
or would I do something like
= (1/2)(3+1)v^2 + (1/2)(9.8)(1.0)
solve for velocity...? and then use this velocity to find the KE
thanks for the help!