Two Point Charge Force Calculation on Left Side

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SUMMARY

The discussion focuses on calculating the force experienced by a point charge located on the left side of a grounded conducting plane, influenced by a negative charge on one side and a positive charge on the other. The relevant formula for electric force, F = Q1Q2/(4π*ε*r²), is highlighted. The participant correctly identifies that the presence of the grounded conductor creates an image charge effect, effectively doubling the influence of the charge on the opposite side. This understanding is crucial for accurately determining the net force acting on the left-side charge.

PREREQUISITES
  • Understanding of electrostatics and Coulomb's law
  • Familiarity with the concept of image charges in electrostatics
  • Knowledge of grounded conducting planes and their properties
  • Basic proficiency in mathematical manipulation of physical equations
NEXT STEPS
  • Study the concept of image charges in electrostatics
  • Learn about grounded conductors and their effects on electric fields
  • Explore advanced applications of Coulomb's law in complex systems
  • Investigate numerical methods for simulating electric forces between multiple charges
USEFUL FOR

Students in physics, electrical engineers, and anyone interested in electrostatics and force calculations involving point charges and conductors.

patm95
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Homework Statement



Two point charges sit on either side of large grounded conducting plane. Give an expression for the force experienced by the charge on the left hand side. There is a neg charge on one side and positive charge on the other side.

Homework Equations



The electric force equation:

F=Q1Q2/4pi*Ep*r^2

The Attempt at a Solution



Well I know that if I have a charge on one side of conductor there will be a force as if there was an opposite charge on the opposite side of the conductor. So my rationale of thinking is that there will be a force on the charge as if there were 2X the charge on the opposite side of the conductor (since there is one there already plus the image) Is this the correct way of thinking? Thanks!
 
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thats what i was thinking when read the question too
 
Great! Thanks!
 

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