Two spheres falling through water..terminal velocity?

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SUMMARY

The discussion focuses on calculating the terminal velocity of a wooden sphere with a diameter of 1.75 cm and a density of 0.85 g/cm³ as it rises through water. The terminal velocity of the glass sphere, which is 0.3 m/s downward, serves as a reference point. The final calculated terminal velocity for the wooden sphere is 3 cm/s in the upward direction. Participants emphasized the importance of unit conversion and understanding the principles of buoyancy and drag forces in fluid dynamics.

PREREQUISITES
  • Understanding of fluid dynamics principles, including buoyancy and drag forces.
  • Knowledge of unit conversion, particularly between grams and kilograms, and centimeters to meters.
  • Familiarity with terminal velocity concepts and calculations.
  • Basic algebra skills for solving equations related to motion in fluids.
NEXT STEPS
  • Study the principles of buoyancy and Archimedes' principle in fluid mechanics.
  • Learn how to calculate drag force using the drag equation.
  • Explore the concept of terminal velocity in different fluids and conditions.
  • Review examples of terminal velocity calculations for various shapes and densities.
USEFUL FOR

Students studying physics, particularly those focusing on fluid dynamics, as well as educators and anyone interested in understanding the behavior of objects in fluids.

imatreyu
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Homework Statement



A glass sphere of diameter 1.75 cm and density 2.5 g/cm^3 falls through water with a terminal velocity of 0.3m/s. A wooden sphere of the same diameter and density 0.85 g/cm^3 is released from the bottom of a tank of water. Determine the terminal velocity with which the wooden sphere rises.

Homework Equations


I have no idea where to start! Could someone point me in the right direction?


The Attempt at a Solution



I converted everything so that all units are in kg or m . . .

But now I have no idea what equation to use, etc. . . Just a hint. . would be nice.

Thank you, in advance!
 
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answer is 3cm/s upward direction
 

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Oh. . .Wow, thank you.
 

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