Two springs connected by a spring

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Homework Help Overview

The problem involves two masses connected by a spring on a frictionless plane, with the goal of finding the natural frequency of oscillation. The discussion centers around the equations of motion and the relationships between the displacements of the masses.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive equations of motion for the system but struggles to manipulate them into a solvable ordinary differential equation (ODE). Some participants suggest defining a new variable to simplify the problem, while others question the correctness of the initial equations based on the interactions between the masses.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to the problem. There is an acknowledgment of potential issues with the original equations of motion, and suggestions for re-evaluating the definitions and relationships involved.

Contextual Notes

Participants are considering the implications of the masses' positions on the forces acting on them, indicating a need to clarify the assumptions about the system's behavior.

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Homework Statement


Two masses, m1 and m2, are connected to each other by a spring with a spring constant k. The system moves freely on a horizontal frictionless plane. Find the natural frequency of oscillation.

Homework Equations


F = -kx
F = ma

The Attempt at a Solution


Let m1 be the mass on the left, and let m2 be the mass on the right.
Let positive be in the direction of m2.

Let x1 be the displacement of m1 onto the spring, and x2 the displacement of m2 onto the spring.

-m_{1}\ddot{x_{1}}=k{x_{1}}

m_{2}\ddot{x_{2}}=-k{x_{2}}

m_{2}\ddot{x_{2}}-m_{1}\ddot{x_{1}}=-k(x_{2}-x_{1})

m_{2}\ddot{x_{2}}-m_{1}\ddot{x_{1}}=-k(\Delta{x})

I tried manipulating this into an ODE, but got nowhere.
 
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What if you define a new variable, say, q = x_2 - x_1?
 
Well, then I would have

m_{2}\ddot{x_{2}}-m_{1}\ddot{x_{1}} = -kq

...which, from what I see, doesn't do a whole lot because I still can't factor the left side to do anything.
 
Well, firstly, the force on the first mass depends on the location of both itself AND the other mass. Think for example if one mass is very far away. Then there would be a big force on the second one.

So your equations of motion are incorrect (total forces should add up to zero).
 

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