- #1
michaelwiggin
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Homework Statement
"A 60kg boy rides down an icy hill of 19º slope while standing on a 2.6kg flat-bottomed bathroom scale. Assume there is no frictional force between the bottom of the scale and the hill. The static friction force the scale exerts on the boy is ____.
Homework Equations
... F = ma
Ff=[tex]\mu[/tex]Fn
Not sure what else... really its the theory of it that's getting me.
The Attempt at a Solution
Well, my understanding is that if there was no friction between the boy and the top of the scale, then while the scale was sliding down the hill, the boy would be sliding downward not only with respect to the hill (as a result of the acceleration of the scale) but also with respect to the scale. But because it asks for the static friction of the scale on the boy, this must mean he's not moving, and thus when determining the friction we can use the usual Ff=mgsin[tex]\theta[/tex] equation.
Thus 60kg(9.8m/s2)(sin19) = 191.4
Any mistakes that you all notice?
Thanks!
-Michael