Two successive rotation (Goldstein problem 4.13)

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SUMMARY

The discussion centers on the Goldstein problem 4.13, which involves demonstrating that two successive rotations through angles Φ1 and Φ2 can be represented as the sides of a spherical triangle, with the angle opposite to Φ defined as the angle between the two axes of rotation. The rotation matrices A1 and A2 are utilized, with their traces given by Tr A1 = 1 + 2 cos(Φ1) and Tr A2 = 1 + 2 cos(Φ2). The relationship between the angles is established through the cosine of the angle ψ between the rotation axes, leading to the conclusion that ψ is indeed the angle opposite to Φ in the spherical triangle.

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  • Understanding of rotation matrices in three-dimensional space.
  • Familiarity with spherical geometry and spherical triangles.
  • Knowledge of the trace of a matrix and its relation to rotation angles.
  • Basic concepts of classical mechanics as outlined in Goldstein's "Classical Mechanics, 3rd edition".
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This discussion is beneficial for students and professionals in physics, particularly those studying classical mechanics, as well as mathematicians interested in geometric interpretations of rotations and transformations in three-dimensional space.

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Homework Statement


Suppose two successive coordinate rotations through angles ##\Phi_1## and ##\Phi_2## are carried out, equivalent to a single rotation through an angle ##\Phi##. Show that ##\Phi_1##, ##\Phi_2## and ##\Phi## can be considered as the sides of a spherical triangle with the angle opposite to ##\Phi## given by the angle between the two axes of rotation.

(Source: Classical Mechanics, 3rd edition, Goldstein, Problem 13, Chapter 4)

Homework Equations


If ##A## is a rotation matrix,
$$Tr~A=1+ 2\cos{\theta}$$
,where ##\theta## is the rotation angle.

The Attempt at a Solution


Let ##R_1## and ##A_1## be the rotation axis (unit vector) and the rotation matrix respectively for the ##\Phi_1## rotation. So we get,
$$A_1R_1=R_1$$
and $$Tr~ A_1 = 1+2 \cos{\Phi_1}$$
In the same way, for ##\Phi_2##,
$$A_2R_2=R_2$$
and $$Tr~ A_2 = 1+2 \cos{\Phi_2}$$
The rotation matrix corresponding to ##\Phi## rotation will be ##A_2A_1##. So we get
$$Tr ~A_2A_1 = 1+2 \cos{\Phi}$$
If the angle between ##R_1## and ##R_2## is ##\psi##, then
$$\cos{\psi}=R_1^TR_2$$
Now I need to show that ##\psi## is the angle opposite to ##\Phi## in the spherical triangle with ##\Phi_1##, ##\Phi_2## and ##\Phi## considered as the sides.
I am not sure if the problem can be solved in this approach.
Any help or suggestion will be appreciated.
 
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I'm not sure how rigorous the derivation needs to be. But if you construct a diagram of the spherical triangle, then the result appears to follow immediately by inspection of the diagram.
 
TSny said:
I'm not sure how rigorous the derivation needs to be. But if you construct a diagram of the spherical triangle, then the result appears to follow immediately by inspection of the diagram.
I was looking for a rigorous derivation.
 
OK. I don't see a rigorous derivation at the moment. For what it's worth, here's the diagram that seems to me to show the result.

upload_2017-9-22_23-48-0.png
Start with a spherical apple. Let a radial line sweep out the arc Φ1 from a to b, slicing the apple along the yellow plane. Continue with two more slicings Φ2 and Φ along the blue and green planes, respectively. Remove the wedge of apple that has been sliced out. The picture above shows peering down inside the apple. The red angle is the angle opposite Φ. This angle is clearly the angle between the yellow and blue planes. The result follows by considering how the angle between the yellow and blue planes is related to the angle between the rotation axes corresponding to Φ1 and Φ2.

Hopefully, someone can provide some hints on constructing a rigorous argument.
 
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