Two Variable 2nd Order Taylor Series Approximation

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SUMMARY

The discussion focuses on deriving the two-variable second-order Taylor series approximation for the function f(x,y) = x^3 + y^3 – 7xy, centered at the point (a,b) = (6,-4). The approximation formula includes first and second partial derivatives evaluated at the center point. Participants emphasize the importance of calculating the partial derivatives and substituting the values into the Taylor series expression to obtain the approximation.

PREREQUISITES
  • Understanding of multivariable calculus
  • Knowledge of partial derivatives
  • Familiarity with Taylor series expansions
  • Ability to evaluate functions at specific points
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  • Study the calculation of partial derivatives for multivariable functions
  • Learn about Taylor series expansions in multiple dimensions
  • Practice deriving second-order Taylor series approximations
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Students and professionals in mathematics, particularly those studying calculus, multivariable functions, and numerical methods for approximation.

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Homework Statement



Derive the Derive the two variable second order Taylor series approximation,
below, to f(x,y) = x^3 + y^3 – 7xy centred at (a,b) = (6,‐4)

f(x,y) ≈ Q(x,y) = f(a,b) + \frac{∂f}{∂x}| (x-a) + \frac{∂f}{∂x}|(y-b) + \frac{1}{2!}[\frac{∂^2f}{∂x^2}| (x-a)^2 + 2\frac{∂^2f}{∂x∂y}\ |(x-a)(y-b)+ \frac{∂^2f}{dy^2}\ |(y-b)^2]

Homework Equations


The Attempt at a Solution


I do not understand the question. Please help me start out. Thanks
 
Last edited:
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Evaluating the Taylor expansion is pretty straightforward. All you need to do is to calculate the partial derivatives, and then evaluate them at the given point. So calculate \frac{\partial f(x,y)}{\partial x}*and then evaluate it at (x=6,y=-4). Then do the same for all other derivatives and plug the numbers you get into the expression.
 

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