- #1

fluidistic

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## Homework Statement

I am trying to use Zangwill's book to calculate the transmisson (T) and reflexion (R) coefficients for an EM plane wave going through 3 layers. (the intermediate layer has a width d).

I am reading pages 604/605, he defines "N+1" as the number of layers in which layer 0 is half infinite (from say ##x=-\infty## to x=0) and layer N is also semi infinite and extends to positive infinite.

The book reaches a system of 2 equations with 2 unknows: [tex]\begin{bmatrix} 1+R \\ (1-R)Z_0^{-1} \end{bmatrix}=\prod _{j=1}^{N-1} \begin{bmatrix} \cos \phi _j && -i Z_j \sin \phi _j \\ -iZ_j ^{-1}\sin \phi _j && \cos \phi _j \end{bmatrix} \begin{bmatrix} T \\ TZ_N^{-1} \end{bmatrix}[/tex] where the 2 unknowns are R and T. In fact I don't understand why these are 2 unknows since when we know one of them we know both of them since R+T must equal 1.

**2. The attempt at a solution**

I have 3 layers so N+1=3, so N=2. So if I use the formula given in the book, the product goes from j=1 to N-1=1 so I have only 1 term for the product.

Then I manually solved the system of equations for T and reached that [tex]T=\frac{2n_1/(c \mu_0 )}{\left ( \frac{-in_2}{c\mu_1} \right ) \sin (n_2 d \omega /c) + \cos (n_2 d \omega /c) \left ( \frac{n_3}{c \mu_2} \right ) + \left ( \frac{n_1}{c\mu_0} \right ) [\cos (n_2 d \omega /c) -\frac{in_2}{c \varepsilon_1} \sin (n_2 d \omega /c) \frac{n_3}{c \mu _2}] }[/tex] where the notation is a bit misleading since ##n_i## is the refractive index of the i'th layer while ##\varepsilon _i## and ##\mu _i## corresponds to the i-1'th layers.

What I don't like about my result is that it depends on ##\varepsilon _i## and ##\mu _i## and given the problem statement I would have hoped to get all in terms of ##n_i## instead but I see no way of reaching that.

Then I'm told to calculate explicitely T and R for particular values of ##n_1##, ##n_2## and ##n_3##. So I don't know where I went wrong...