Type 1 Projectile with an initial vertical velocity

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SUMMARY

The discussion focuses on calculating the time it takes for a peach pit, thrown horizontally at 7.0 m/s from an elevator moving upward at 8.5 m/s, to hit the ground 17 meters below. The correct approach involves using the kinematic equation d = vt + 1/2at², leading to the equation -17 = 8.5t - 4.9t². The solution requires applying the quadratic formula, resulting in a time of 2.92 seconds for the pit to land.

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A rude tourist throws a peach pit horizontally with a 7.0 m/s velocity out of an elevator cage. The ground is 17 m below. How long will it take for the pit to land if the elevator is moving upward at a constant 8.5 m/s velocity?



d=volt + 1/2at2



My attempt that continuously doesn't work is:
-17=(8.5)(t)+1/2(-9.8)(t2)
-17=8.5t - 4.9t2


The answer is 2.92s.. I'm just not quite sure how to get there. Please show all the steps in your solution.. I'm drawing a blank on how to solve for t!



Thank you!
 
Last edited:
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0=17+8.5t-4.9t^2

Then use the quadratic equation to solve it
 
leachlife4 said:
0=17+8.5t-4.9t^2

Then use the quadratic equation to solve it

oh right! i forgot about the quadratic equation.. got it now! thanks!
 

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