U substitution and integration by parts

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SUMMARY

The discussion centers on the use of U substitution and integration by parts in solving integrals. Participants highlight that integration by parts is beneficial when dealing with products of functions, but may not always be the most efficient method. For example, the integral \(\int(u-1)\sqrt{u}du\) can be resolved more straightforwardly using the power rule rather than integration by parts. The conversation emphasizes the importance of selecting the appropriate method based on the integrand's structure.

PREREQUISITES
  • Understanding of integral calculus concepts
  • Familiarity with U substitution technique
  • Knowledge of integration by parts method
  • Ability to apply the power rule for integration
NEXT STEPS
  • Study the application of U substitution in various integrals
  • Explore the integration by parts formula and its derivation
  • Practice solving integrals using the power rule
  • Analyze examples where integration by parts is less efficient than other methods
USEFUL FOR

Students of calculus, mathematics educators, and anyone looking to deepen their understanding of integration techniques and their applications.

robertjford80
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I would think because of this

Screenshot2012-05-23at73955PM.png


The following problem:

Screenshot2012-05-23at72700PM.png


At this stage they should use integration by parts:

Screenshot2012-05-23at74154PM.png


However, maybe integration by parts is only useful when one of the parts is e^x ln or a trigonometric formula.
 
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Integration by parts can be useful whenever the integrand is a product of two functions. But it is not always the easiest method to use. For instance, the integral \int(u-1)\sqrt{u}du=\int(u^{3/2}-u^{1/2})du can easily be solved using the power rule in reverse. Of course, you could solve it using integration by parts as well, but it's just more work than is necessary.
 
good, thanks.
 
What would be your u and what would be your dv?

Using integration by parts might work, but I feel that even if it does work it will be much more work than using u substitution.Is the problem here that you don't find the u substitution they used to be 'legal'?
 
Yea, it doesn't seem legal, because I thought you couldn't take the product of two functions in an integrand.
 
robertjford80 said:
Yea, it doesn't seem legal, because I thought you couldn't take the product of two functions in an integrand.

You need to work on being more precise. The integrand of \int_0^1 x^2 \mathrm{d}x is the product of two functions but is clearly integrable.
 

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