(UCM) Maximum Rev. Per Minute Using Length and Acceleration

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SUMMARY

The discussion focuses on calculating the maximum revolutions per minute (RPM) of a rotating arm with a length of 10 meters, where the acceleration must not exceed 5g (with g defined as 10 m/s²). The solution involves using the centripetal acceleration formula, Ac = v²/r, leading to a maximum velocity of approximately 7.07107 m/s. This velocity corresponds to a period of 4.44288 seconds for one revolution, resulting in a maximum of 22.2144 RPM when adjusted for the 5g limit.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula (Ac = v²/r)
  • Familiarity with angular motion equations (T = (2πR)/v)
  • Basic knowledge of gravitational acceleration (g = 10 m/s²)
  • Ability to perform unit conversions and calculations involving RPM
NEXT STEPS
  • Study the derivation and applications of centripetal acceleration in circular motion
  • Learn about angular velocity and its relationship with linear velocity
  • Explore the effects of varying radius and acceleration on rotational dynamics
  • Investigate real-world applications of RPM calculations in engineering and physics
USEFUL FOR

This discussion is beneficial for physics students, aerospace engineers, and anyone interested in the dynamics of rotational motion and its practical applications in engineering contexts.

oziemaster
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Homework Statement



An astronaut rotates at the end of a test machine whose arm has a length of 10m. If the acceleration she experiences must not exceed 5g (g = 10 ms^-2), what is the maximum number of revolutions per minute of the arm?

Homework Equations



T = (2πR)/v

V = (2πR)/T

Ac = V2/r

The Attempt at a Solution



Ac = v2/r

Plug in acceleration given and radius (from length of 10m): 10 = v2/5

5*10 = 50

50 = v2

v = 7.07107

T = 2π*5/7.07107

T = 4.44288 revolutions for 1g

Multiply 4.44288 by 5 = 22.2144 RPM?
 
Last edited:
Physics news on Phys.org
Hi Oziemaster,

Do you know what "g" is?

ehild
 

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