I Un-skewing a skew symmetric matrix (for want of a better phrase)

Trying2Learn
Messages
375
Reaction score
57
TL;DR
A better term for the process of creating a skew symmetric matrix
Hello

Say I have a column of components

v = (x, y, z).

I can create a skew symmetric matrix:

M = [0, -z, y; z, 0; -x; -y, x, 0]

I can also go the other way and convert the skew symmetric matrix into a column of components.

Silly question now...

I have, in the past, referred to this as "skewing a column into a skew symmetric matrix" or "unskewing the skew symmetric matrix."

Is there a better phrase to describe this? (mostly, the second one).

(And forget the algebra and the reasons... I just need the term that best describes the process.)
 
Physics news on Phys.org
Representing a skew symmetric 3x3 matrix by a vector in ##\mathbb{R}^3## would be the fancy way of saying it.
 
Thread 'How to define a vector field?'
Hello! In one book I saw that function ##V## of 3 variables ##V_x, V_y, V_z## (vector field in 3D) can be decomposed in a Taylor series without higher-order terms (partial derivative of second power and higher) at point ##(0,0,0)## such way: I think so: higher-order terms can be neglected because partial derivative of second power and higher are equal to 0. Is this true? And how to define vector field correctly for this case? (In the book I found nothing and my attempt was wrong...

Similar threads

Replies
14
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
7
Views
5K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
6K
Replies
12
Views
5K