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Introductory Physics Homework Help
"Uncertainity Product for Particle in 1-D Box
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[QUOTE="RPinPA, post: 6059486, member: 651116"] I think you mean the uncertainty in momentum. I"m a little rusty in QM but I believe what you just calculated is the expectation value of p[SUP]2[/SUP]2, <p[SUP]2[/SUP]>. Momentum is not a single number (which would violate the uncertainty principle). I believe the average value of p is 0, so the variance in p (the square of Δp) is <p[SUP]2[/SUP]> - <p>[SUP]2[/SUP] = <p[SUP]2[/SUP]>. So the expression you gave for p, the square root of the variance, is actually the momentum uncertainty you're looking for. [/QUOTE]
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"Uncertainity Product for Particle in 1-D Box
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