Understand Contravariant Transformations b/w Coordinate Systems

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SUMMARY

The discussion focuses on the application of contravariant transformations between coordinate systems, specifically converting Cartesian coordinates to polar coordinates using the formula Vj = (∂yj/∂xi) * Vi. The user successfully demonstrates this transformation, resulting in the vector being converted to . The application of the Einstein summation convention is confirmed, and suggestions for improved notation are provided, including using prime symbols for components and variable names for clarity.

PREREQUISITES
  • Understanding of contravariant transformations
  • Familiarity with coordinate systems, specifically Cartesian and polar coordinates
  • Knowledge of partial derivatives and their application in transformations
  • Basic grasp of the Einstein summation convention
NEXT STEPS
  • Study the implications of contravariant transformations in different coordinate systems
  • Explore the use of the Einstein summation convention in tensor calculus
  • Learn about covariant transformations and their differences from contravariant transformations
  • Investigate the application of vector notation in polar coordinates, including the use of unit vectors
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Students and professionals in physics and engineering, particularly those working with vector calculus and coordinate transformations, will benefit from this discussion.

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I am trying to make sure that I have a proper understanding of contravariant transformations between coordinate systems.

The contravariant transformation formula is:

Vj = (∂yj/∂xi) * Vi

where Vj is in the y- frame of reference and Vi is in the x-frame of reference. Einstein summation convention is used here.

As an example of applying this formula, I tried to convert a Cartesian vector to a polar coordinates vector to see what the output would be. Here is how that process went:

Vi = <x,y>
x1 = x
x2 = y (These were the coordinate axes in the x-frame)

y1 = r
y2 =θ (These were the axes in the y-frame)

r(x,y) = sqrt(x2 + y2)
θ(x,y)= tan-1(y/x)
(∂r/∂x) = x/sqrt(x2 + y2)
(∂r/∂y) = y/sqrt(x2 + y2)
(∂θ/∂x) = -y/(x2 + y2)
(∂θ/∂x) = x/(x2 + y2)Applying all of this information into the contravariant transformation formula, I get:

V1 (in the y-frame) = [V1(x-frame) * (∂y1/∂x1)] + [V2(x-frame) * (∂y1/∂x2)] =[ x * (∂r/∂x) ] + [y * (∂r/∂y)]

= (x2 + y2) / sqrt(x2 + y2) = r2/r = r

V2 (in the y-frame) = [V1(x-frame) * (∂y2/∂x1)] + [V2(x-frame) * (∂y2/∂x2)] =[ x * (∂θ/∂x) ] + [y * (∂θ/∂y)]

= -xy/r2 + xy/r2 = 0

In short, my contravariant transformation from Cartesian to polar coordinates turned the vector <x,y> to <r,0>.

Is this the correct result. Am I appropriately and correctly applying the contravariant transformation formula or do you use this transformation in some different way?
 
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Yes, you have just taken the position vector and it should be a familiar result that this vector is ##r \vec e_r## in polar coordinates in the plane.

A suggestion regarding notation, the more standard notation would be to use a prime to denote the components in one of the systems. It is also easier to keep track of things if you use the variable names instead of numbers to label the different components, i.e., ##V^r##, ##V^\theta##, etc.
 
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